How to sort an List of object arrays in ascending order

1 answer

I have an hibernate entity class:

    @Entity     @Table(name = "grade")     @JsonIgnoreType     public class StudentMaster implements Serializable {      @Id     @GeneratedValue(strategy = GenerationType.IDENTITY)     @Column(name = "grade_id", unique = true, nullable = false)     private Integer gradeId;      @Column(name = "grade_name")     private String gradeName;     //getter and setter    } 

I have written a query that return a list of object array: String query = select T.gradeId, T.gradeName from grade where available = 1;

This return a list of object array

    List<Object[]> list = session.createQuery(query.toString()).list(); 

List is coming like

    [0]      >[0] = 5001      >[1] = "10"     [1]      >[0] = 5002      >[1] = "11"     [2]      >[0] = 5003      >[1] = "4"     [3]      >[0] = 5004      >[1] = "18"        and so on.... 

I am trying to sort this in ascending order like 4, 10, 11, 18 I tried with the below code snippet but didn't work

   Collections.sort(list, new Comparator<StudentMaster>() {         public int compare(StudentMaster s1, StudentMaster s2) {             return s1.getGradeName().compareTo(s2.getGradeName());         }     }); 

can someone help me here. I am learning myself and new to coding so need help. Thank you

All answers to this question, which has the identifier 61237223

The best answer:

I would suggest to let DB to do its best and sort it for you. Just add order by to your query.

Update:

Since you want to order by integer value stored as string, you need to convert it to integer, using TO_NUMBER or specific SQL dialect syntax. In-memory sorting could be implemented like this :

new Comparator<Object[]>() {  public int compare(Object[] o1, Object[] o2) {  return Integer.valueOf((String) o1[1]).compareTo(Integer.valueOf((String) o2[1]));  }  }); 

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